How do you implement a function using multiplexer?
There are certain steps involved in it:
- Step 1: Draw the truth table for the given number of variable function.
- Step 2: Consider one variable as input and remaining variables as select lines.
- Step 3: Form a matrix where input lines of MUX are columns and input variable and its compliment are rows.
Is mux used to implement Boolean logic function?
Implementation of Boolean function through multiplexer can be done by various multiplexers depending upon the select lines. Implementation of Boolean functions can be done by various methods, but in this particular paper stress is more on multiplexers.
Can we implement multiple Boolean functions using a single multiplexer?
In this paper we have seen that Boolean functions can be implemented using different multiplexers, 2×1, 4×1 or 8×1. With the help of Shannon expansion theorem, complicated Boolean functions can be made easy, in implementing through multiplexers.
How do you implement a Boolean function?
Any Boolean function can be implemented using only AND and INVERT gates since the OR function can be generated by a combination of these two gates, as shown in Figure 2.20(a). It follows that these two gates can implement any arbitrary Boolean function and they are said to form a complete set.
How Boolean is implemented using decoder?
Combinational Logic Implementation using Decoder – input variables. Since any boolean function can be expressed as a sum of minterms, a decoder that can generate these minterms along with external OR gates that form their logical sums, can be used to form a circuit of any boolean function.
What is multiplexer truth table?
The block diagram of 4×1 Multiplexer is shown in the following figure. One of these 4 inputs will be connected to the output based on the combination of inputs present at these two selection lines. Truth table of 4×1 Multiplexer is shown below. Selection Lines. Output.
Is used to implement the Boolean functions?
Explanation: To implement a Boolean function logic gates are used.
How do you implement a function using 8 1 multiplexer?
The given function is in terms of minterms and is to be implemented using a 8:1 MUX. An 8:1 MUX has three select lines, whereas the given function is a 4 variable function. Hence a logic is needed to give combination of A as inputs while only B, C and D as select line inputs. The method for the same is described below.
How do you solve a multiplexer?
- Firstly truth table is constructed for the given multiplexer.
- Select lines in multiplexer are considered as input for the truth table.
- Output in truth table can be four forms i.e. ( 0, 1, Q, Q’).
- Now with the help of truth table we find the extended expression.
How do you implement an 8 to 1 multiplexer?
All you need to do is connect the eight inputs to GND (Ground) or VDD to match the 0s and 1s of the Q output of the truth table. What this tells us is that the CD4512 is an 8:1 multiplexer. The three selection inputs, A, B, and C are used to select one of the eight D0 to D7 data inputs.
Can a decoder function as a de multiplexer justify?
A decoder with an enable input can function as a Demultiplexer. A demultiplexer is a circuit that receives information on a single line and transmits this information on one of 2n possible output lines.
How to implement a Boolean function through multiplexer?
Implementation of Boolean function through multiplexer can be done by various multiplexers depending upon the select lines. Implementation of Boolean functions can be done by various methods, but in this particular paper stress is more on multiplexers. Through Shannon expansion theorem,it is easy
Are there any problems on multiplexer?
There are several problems on multiplexer, which are solved to get the desired circuit. In this section, you will learn, How to implement a boolean expression in a multiplexer?
How to implement the Boolean expression f (A B B C) = ∑ M?
Implement the boolean expression F (A, B, C) = ∑ m (0, 2, 5, 6) using 4 : 1 multiplexer. In the given boolean expression, there are 3 variables. We should use 2 3 : 1 = 8 : 1 multiplexer.
What are the inputs of multiplexer?
The implementation table has all the inputs (D 0, D 1, D 2, D 3 ,…) for the multiplexer, under which, all the minterms are listed in two rows. The first row consists of all minters where A is complemented and the second row has the remaining minterms where A is in uncomplemented form.